Notes for Complex Analysis

From this day forward, I’ll be reading the book $\textit{Complex Analysis (Princeton Lectures in Analysis, No. 2)}$ for at least 1 hour per day until I finish the book. I’ll put anything I thought interesting/important on this page.

Ch1
A $\textbf{holomorphic}$ function (defined to be a function with a first derivative) is infinitely many times complex differentiable. i.e. the existence of the first derivative will guarantee the existence of derivatives of any order.

$\textbf{Cauchy-Riemann}$ equations: \(\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} \ and \ \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}\) (equivalent to $\frac{\partial f}{\partial \overline{z}} = 0$)
$f = u + iv$, f is complex differentiable at a complex point iff(if and only if) the partials of u and v satisfy the Cauchy-Riemann equations at that point.

A function that is $\textbf{analytic}$ i.e. has a power series expansion at every point on $\Omega$ is also holomorphic here. The reverse is also true.

A $\textbf{primitive}$ for $f$ on $\Omega$ is a functioin $F$ that is holomorphic on $\Omega$ and such that $F’(z)=f(z)$ for all $z \in \Omega$.
If a continuous function $f$ has a primitive $F \in \Omega$ and $\gamma$ is a curve in $\Omega$ that begins at $\omega_1$ and ends at $\omega_2$, then

\[\int_\gamma f(z) dz = F(\omega_2) - F(\omega_1)\]

Thus, it follows naturally that if $\gamma$ is a closed curve in an open set $\Omega$, and $f$ is continuous and has a primitive in $\Omega$, then

\[\int_\gamma f(z)dz = 0\]

Ch2
a